8^4x-3=32^2x+1

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Solution for 8^4x-3=32^2x+1 equation: 



8^4x-3=32^2x+1

We move all terms to the left:

8^4x-3-(32^2x+1)=0

We get rid of parentheses

8^4x-32^2x-1-3=0

We add all the numbers together, and all the variables

8^4x-32^2x-4=0

We move all terms containing x to the left, all other terms to the right

8^4x-32^2x=4

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